#include #include char* createStr () { static char str [20] = "my"; return str; } int main () { char a [20]; strcpy (a,createStr ()); //this will copy the returned value of createStr () into a [] printf ("%s",a); If the function needs to modify a dynamically allocated (i.e. heap-allocated) string buffer from the caller, you must pass in a pointer to a pointer. In C, function arguments are passed by value. As we know that we can create a pointer of any data type such as int, char, float, we can also create a pointer pointing to a function. Passing CHAR array to function // student structure struct student { char id[15]; char firstname[64]; char lastname[64]; float points; }; Point to be noted that when you do point = "blah" you are creating a string literal, and any attempt to modify is Undefined behaviour, so it should really be const char * To Fix - pass a pointer to a pointer as @Hassan TM does, or return the pointer as below. const char *ptrch { return "asd"; } ... const char* point = ptrch(); Amend Stack-Allocated String in a Function. , 'j' } ; function ( array ) ; } I do not agree with you. So, we will be using that idea to pass structure pointer to a function. In our first example, we will pass the string to a function that is done for any other ordinary array (i.e., float, integer, or double array). A structure can be passed to any function from main function or from any sub function. Passing When incrementing or using array syntax ( []), the first increments one element ( sizeof (*pointer) ), while the second jumps to the end of the array. How to pass and return array from function in C? - Codeforwin

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